Ive always struggles with remembering how to properly hook up a
speaker cab to a head. *Ive also found that if you understand what is going on youll remember it better. *Maybe this will help a few of you guys out if you find yourself getting confused like i often do.
when speakers are wired in series the impedence is simply added together. *Suppose you have 2 8
Ohm speakers in series. *8 Ohms + 8 Ohms = 16 Ohms.
when speaker are wired in parallel follow this equation:
1/Req = 1/R1 + 1/R2 + .....
So suppose you have 2 16 Ohm speakers in parallel the total impedence is:
1/Req = 1/16 + 1/16 * ==> 2/16 * * *now take the reciprical to find R equivilance (Req) which gives us 16/2 or 8 Ohms. *
on the back of your amp when you plug a cab into ONE speaker output you have set up your cab in series with you head. *when you use MORE THAN ONE inputs you have set up your cab in parallel with your head. *That is why when you plug 2 8 Ohm cabinets into 1 head the total impedence is 4 Ohms. *
Now you really dont need all this math stuff to hook up 2 identical cabinets but say you have a 16 Ohm cab and a 4 Ohm cab and you want to plug them both in to the same head. *
1/Reg = 1/16 + 1/4 *==> 5/16, taking the reciprical again yields 16/5 ==> 3.2 Ohm! *notice this is actually less than 4 ohms. *this is very important because whenever you have 2 speakers in parallel the total impedence will be less than the smallest speaker ohm value. *
And as stated in other posts be sure the total impedence is the same or higher than what is set on your head. *other wise you amp will overheat. *Another thing to consider is if possible run your head at the highest Ohm value possible. *youre amp works harder at 4 Ohms than at 16 Ohms. *You dont get as much power but you amp will last longer. *(note: having the head at 4 ohms and the speakers at 16 ohms will give you less power than your head and speakers both set to 16!)
hopes this helps
cody * *