That is very helpful, and would seems to work (from what I understand). But wouldnt it be the case that when the switch is up, both the diode and capacitor will be controlled by the pot? In the warmoth thread you linkd, it seemed that that was creating some problems.
Could I do this?
blank...................0...0---- soldered to the grounded diodes
blank...................0...0----soldered to the signal from volume, and then to the 1/4 in jack.
blank...................0...0.....blank
That would just be an on off switch right?
Also, I think there may be complication/mistake in your diagram. When the pot is pulled out, the signal isnt in the circuit anymore.
so to correct this, I think it would need to be like this.
volume pot lead....0...0---- soldered to the grounded diodes
soldered together--0--0----and soldered to the outside non-grounded lug of the tone pot
volume pot lead----0...0.....blank
This would have the effect of a standard tone control when in, and the tone control in parallel with the diode circuit when out.
EDIT: I think this is the relevant part of the black ICe instructions. I think this may be better than either of our ideas, becauce it makes it so that the capacitor and diode circuits do not interact, and both can be controlled by the pot.